Question

Hitunglah pH larutan berikut ini.
a.H2SO4 0.05 M
B.HNO3 10^-3 M
C.NaOH 0.1 M
D.Ca(OH)2 10^-4 M
E.Ba(OH)2 0.005 M

minta tolong

Answer 1

A. H2SO4 0,05 M
[H+] = M x valensi asam
= 0,05 x 2
= 0,1 --------> pH = 1

B. HNO3 10^-3 M
[H+] = M x valensi asam
= 10^-3 x 1
= 10^-3 ----------> pH = 3

C. NaOH 0,1 M
[OH-] = M x valeni basa
= 0,1 x 1
= 10^-1 --------------> pH = 13

D. Ca(OH)2 10^-4 M
[OH-] = M x valensi basa
= 10^-4 x 2
= 2 x 10^-4 ----------------> pH = 10 + log 2

E. Ba(OH)2 0,005 M
[OH-] = M x valensi basa
= 0,005 x 2
= 0,01 -------------> pH = 12