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= 0,006 : 0,05
= 0,12
pOH= - log OH-
= - log 1,2 x 10pangkat -1
= 1 - log 1,2
pH + POH = 14
pH + 1 - log 1,2 = 14
pH = 13 + log 1,2
b.
Mr Ca(OH)₂ = 74
b.
Ka = α²M