Question

Hitunglah pH larutan 500mL HCN 0,1 yang dicapur dengan 500mL KOH 0,1 M! (Ka HCN = 10-6) (-6) nya pangkat yaa... makasih

Answer 1

HCN + KOH --> KCN + H2O (mmol)
m 50 50 — —
r 50 50 50 50
s — — 50 50

[CN–]
= 50/1000
= 0,05 M

[OH–]
= √Kw/Ka.[CN–]
= √10^–14/10^–6.(0,05)
= √5.10^-10
= √5.10^–5 M

pOH
= –log [OH–]
= –log (√5.10^–5)
= 5–log √5

pH
= 14–(5–log √5)
= 9+log √5

semoga membantu.. :)