Hitunglah ph dari
a.500ml HNO3 0,01M
b.200ml H2so4 0,05M
c.100ml LiOH 0,03M
d.50ml Ba(Oh)2 0,05M
a.500ml HNO3 0,01M
b.200ml H2so4 0,05M
c.100ml LiOH 0,03M
d.50ml Ba(Oh)2 0,05M
Risep
![a.~[H^+]=a.M=1.10^{-2}~M \\ \\ pH=-log10^{-2}=2](https://tex.z-dn.net/?f=a.%7E%5BH%5E%2B%5D%3Da.M%3D1.10%5E%7B-2%7D%7EM+%5C%5C++%5C%5C+pH%3D-log10%5E%7B-2%7D%3D2 "a.~[H^+]=a.M=1.10^{-2}~M \\ \\ pH=-log10^{-2}=2")
![b.~[H^+]=a.M=2.5.10^{-2}=10^{-1}~M \\ \\ pH=-log10^{-1}=1](https://tex.z-dn.net/?f=b.%7E%5BH%5E%2B%5D%3Da.M%3D2.5.10%5E%7B-2%7D%3D10%5E%7B-1%7D%7EM+%5C%5C+%5C%5C+pH%3D-log10%5E%7B-1%7D%3D1 "b.~[H^+]=a.M=2.5.10^{-2}=10^{-1}~M \\ \\ pH=-log10^{-1}=1")
![c.~[OH^-]=b.M=1.3.10^{-2}=3.10^{-2}~M \\ \\ pOH=-log3.10^{-2}=2-log3 \\ \\ pH=14-(2-log3)=12+log3](https://tex.z-dn.net/?f=c.%7E%5BOH%5E-%5D%3Db.M%3D1.3.10%5E%7B-2%7D%3D3.10%5E%7B-2%7D%7EM+%5C%5C+%5C%5C+pOH%3D-log3.10%5E%7B-2%7D%3D2-log3+%5C%5C++%5C%5C+pH%3D14-%282-log3%29%3D12%2Blog3 "c.~[OH^-]=b.M=1.3.10^{-2}=3.10^{-2}~M \\ \\ pOH=-log3.10^{-2}=2-log3 \\ \\ pH=14-(2-log3)=12+log3")
![d.~[OH^-]=b.M=2.5.10^{-2}=10^{-1}~M \\ \\ pOH=-log10^{-1}=1 \\ \\ pH=14-1=13](https://tex.z-dn.net/?f=d.%7E%5BOH%5E-%5D%3Db.M%3D2.5.10%5E%7B-2%7D%3D10%5E%7B-1%7D%7EM+%5C%5C+%5C%5C+pOH%3D-log10%5E%7B-1%7D%3D1+%5C%5C++%5C%5C+pH%3D14-1%3D13 "d.~[OH^-]=b.M=2.5.10^{-2}=10^{-1}~M \\ \\ pOH=-log10^{-1}=1 \\ \\ pH=14-1=13")
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