Hitunglah ph dari 100ml larutan HCL ber-ph 1 ditambahkan dengan 100ml larutan ber-ph 2? tolong di je.... Question from @Ochaline

September 2018 2 17 Report

Dzaky111 Dik : V1 = 100 ml
   pH1 = 1 ⇒ [H+] = 0,1 M
   V2 = 100 ml
   pH2 = 2 ⇒ [H+] = 0,01 M
Dit : pH campuran = .....
Jwb : Mc = (M1V1 + M2V2)/(V1 + V2)
   = (0,1 x 100 + 0,01 x 100)/(100 +100)
   = (10 + 1)/200
   = 11/20
   = 0,055 M
   pH = -log[H+]
      = -log 0,055
      = 3 - log 55

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Ochaline @Dzaky111 makasih

Risep $pH =1 \rightarrow [H^+]_1=10^{-1} \\ \\ pH =2 \rightarrow [H^+]_2=10^{-2} \\ \\ \\ ~[H^+]_{camp}= \frac{[H^+]_1.V_1+[H^+]_2.V_2}{V_1+V_2} \\ \\ = \frac{0,1.100+0,01.100}{200} \\ \\ = \frac{10+1}{200} \\ \\ =0,055=5,5.10^{-2}~M$

$pH=-log[H^+] \\ \\ =-log5,5.10^{-2} \\ \\ =2-log5,5$

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