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maka
pada segitiga ADE
AE = 10 ( triple pitagoras 6,8,10)
AE ≈ AC
10 : 20
1 : 2
AD ≈ AB
1 : 2
8 : 16
BC ≈ ED
1 : 2
6 : 12
maka
panjang BE = AB - AE = 16 - 10 = 6 cm
panjang BC = 6 cm
mencari AB
mencari BC
mencari BE
be = ab - ae
= 16 - 10
= 6