Question

hitunglah nilai x dan y pada soalnya berikut






tolong waktu nya udah mepet bangat ​

Answer 1

Verified answer

Phytagoras

[tex]x = \sqrt{ {12}^{2} + {5}^{2} } \\ x= \sqrt{144 + 25} \\ x = \sqrt{169} = 13 \\ \\ y + 5 = \sqrt{ {20}^{2} - {12}^{2} } \\ y + 5 = \sqrt{400 - 144} \\ y + 5 = \sqrt{256} \\ y + 5 = 16 \\ y = 16 - 5 \\ y = 11[/tex]

Answer 2

x = √12² + 5²

= √(12(12) + (5(5)

= √144 + 25

= √169

= √13²

= 13

y = √20² - 12² - 5

= √(20(20) - (12(12) - 5

= √(400 - 144) - 5

= √(256) - 5

= √16² - 5

= 16 - 5

= 11