Jawab:
limit (x->∞) √(ax² +bx + c) - √(px² + qx + r)
jika a= p ,limit = (b - q) / (2√a)
Penjelasan dengan langkah-langkah:
lim(x→ ∞) √(4x² -3) - 2x + 1
lim(x→∞ ) √(4x² -3) - √(2x - 1)²
lim(x→∞) √(4x² - 3) - √(4x² - 4x + 1)
a= p= 4
b= 0
q= - 4
limit = (b- q) /2√a
limit = (0 -(-4)) /(2 √4)
limit = 4/4 = 1
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Verified answer
Jawab:
limit (x->∞) √(ax² +bx + c) - √(px² + qx + r)
jika a= p ,limit = (b - q) / (2√a)
Penjelasan dengan langkah-langkah:
lim(x→ ∞) √(4x² -3) - 2x + 1
lim(x→∞ ) √(4x² -3) - √(2x - 1)²
lim(x→∞) √(4x² - 3) - √(4x² - 4x + 1)
a= p= 4
b= 0
q= - 4
limit = (b- q) /2√a
limit = (0 -(-4)) /(2 √4)
limit = 4/4 = 1