[ASAM BASA | XI SMA]
pH = 9,62 = 10-log 2,4
pH = -log [H⁺]
10-log 2,4 = -log [H⁺]
2,4 x 10⁻¹⁰ = [H⁺]
[OH⁻] = [Kw]/[H⁺]
[OH⁻] = 10⁻¹⁴/2,4 x 10⁻¹⁰
[OH⁻] = 4,166 x 10⁻⁵
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[ASAM BASA | XI SMA]
pH = 9,62 = 10-log 2,4
pH = -log [H⁺]
10-log 2,4 = -log [H⁺]
2,4 x 10⁻¹⁰ = [H⁺]
[OH⁻] = [Kw]/[H⁺]
[OH⁻] = 10⁻¹⁴/2,4 x 10⁻¹⁰
[OH⁻] = 4,166 x 10⁻⁵