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dit : kll lingkaran
jwb: L= phi.r2(pangkat 2)
1256=3,14.r2
1256:3,14=r2
400=r2
r=akar 400
r= 20
kll lingkaran= 2phi.r
=2.3,14.20
= 125,6 cm
1256 =3,14 x r2
1256:3,14=r2
400=r2
akar400=r
20=r
keliling=phi X d
k=3,14 X 40
k=125,6 cm