↘️CARA↙️
1. a = 27
r = -1/3
rumus = Sn = a(r^n - 1)/ (r-1)
= S10 = 27 (-1/3)^10 - 1) / (-4/3)
= (-59048/2187) / (-4/3)
= 14072/729
= 20 (122/729) <= Jawaban
2. U4 = ar³ = -4
U9 = ar^8 = 128
(ar³)r^5 = 128
-4 r^5 = 128
. r = -2
a = 1/2
S10 = (1/2)(-2^10 - 1)/ (-2-1)
= -170,5 <= Jawaban
3. Sn = a(r^n - 1)/ (r-1)
255 = 1(2^n - 1) / (2 - 1)
255 = 2^n -1
256 = 2^n
2^8 = 2^n
n = 8 <= Jawaban
4. r = 1/3
a = 18
Rumus = S tak hingga = a / (1 - r)
= 18 / (2/3)
= 27 <= Jawaban
5. U1 = a = 9
S tak hingga = a / (1 - r)
32 = 9 / (1 - r)
32 - 32r = 9
r = 23/32 <= Jawaban
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Hitunglah jumlah deret geometri 27 - 9 + 3 - .... Sampai 10 suku.
↘️CARA↙️
1. a = 27
r = -1/3
rumus = Sn = a(r^n - 1)/ (r-1)
= S10 = 27 (-1/3)^10 - 1) / (-4/3)
= (-59048/2187) / (-4/3)
= 14072/729
= 20 (122/729) <= Jawaban
2. U4 = ar³ = -4
U9 = ar^8 = 128
(ar³)r^5 = 128
-4 r^5 = 128
. r = -2
a = 1/2
S10 = (1/2)(-2^10 - 1)/ (-2-1)
= -170,5 <= Jawaban
3. Sn = a(r^n - 1)/ (r-1)
255 = 1(2^n - 1) / (2 - 1)
255 = 2^n -1
256 = 2^n
2^8 = 2^n
n = 8 <= Jawaban
4. r = 1/3
a = 18
Rumus = S tak hingga = a / (1 - r)
= 18 / (2/3)
= 27 <= Jawaban
5. U1 = a = 9
S tak hingga = a / (1 - r)
32 = 9 / (1 - r)
32 - 32r = 9
r = 23/32 <= Jawaban