Question

Hitunglah isi benda putar yang terjadika,jika y=\sqrt{x} di putar mengelilingi sumbu x sejauh 360°,garis x=1 & garis x=4? tolong ya jawaban a.. ;)

Answer 1

y = √x ---> y^2 = x
V = π ∫ y^2 dx
= π ∫ x dx
= π [ 1/2 x^2 ] 
= 1/2 π [ x^2 ] ---> batas x1 = 1, x2 = 4
= 1/2 π [ (4)^2 - (1)^2 ]
= 1/2 π [ 16 - 1 ]
= 15π/2 satuan volume