Question

hitunglah hasil dari operasi bilangan berpangkat berikut a.(-5)³+(-5)²+(-5)¹+(-5)⁰. b.2^-1 + 3^-1​

Answer 1

1. (-5)^3 + (-5)^2 + (-5)^1 + (-5)^0

= (-5 × -5 × -5) + (-5 × -5) + -5 + 1

= (-125) + 25 + -5 + 1

= (-100) + -5 + 1

= (-105) + 1

= (-104)

2. 2^-1 + 3^-1

= 1/2^1 + 1/3^1

= 1/2 + 1/3

= (6 ÷ 2) × 1 + (6 ÷ 3) × 1/6

= (3 × 1) + (2 × 1)/6

= 3 + 2/6

= 5/6

Answer 2

a

[tex] {( - 5)}^{3} + {( - 5)}^{2} + {( - 5)}^{1} + {( - 5)}^{0} = [/tex]

[tex] - 125 + 25 + ( - 5) + 1 = [/tex]

[tex] - 125 + 25 - 5 + 1 = [/tex]

[tex] - 100 - 5 + 1 = [/tex]

[tex] - 105 + 1 = [/tex]

[tex] - 104[/tex]

b

[tex] {2}^{ - 1} + {3}^{ - 1} = [/tex]

[tex] \frac{1}{2} + \frac{1}{3} = [/tex]

[tex] \frac{3}{6} + \frac{2}{6} = [/tex]

[tex] \frac{3 + 2}{6} = [/tex]

[tex] \frac{5}{6} [/tex]