Hitunglah [H3O+] dan pH larutan asam sianida HCN konsentrasi 0.049 dengan ka:4.0 × 10^10 mohon dijawab beserta jalan kerjanya tp klw tidak bisa gpp jawabannya saja
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![[H_3O^+]= \sqrt{Ka.M} \\ \\ = \sqrt{4.10^{-10}.4,9.10^{-2}} \\ \\ = \sqrt{19,6.10^{-12}} \\ \\ =4,43.10^{-6} \\ \\ pH=-log4,43.10^{-6}=6-log4,43](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D+%5Csqrt%7BKa.M%7D+%5C%5C++%5C%5C+%3D+%5Csqrt%7B4.10%5E%7B-10%7D.4%2C9.10%5E%7B-2%7D%7D+%5C%5C++%5C%5C+%3D+%5Csqrt%7B19%2C6.10%5E%7B-12%7D%7D+%5C%5C++%5C%5C+%3D4%2C43.10%5E%7B-6%7D+%5C%5C++%5C%5C+pH%3D-log4%2C43.10%5E%7B-6%7D%3D6-log4%2C43+++ "[H_3O^+]= \sqrt{Ka.M} \\ \\ = \sqrt{4.10^{-10}.4,9.10^{-2}} \\ \\ = \sqrt{19,6.10^{-12}} \\ \\ =4,43.10^{-6} \\ \\ pH=-log4,43.10^{-6}=6-log4,43")
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