Jawaban:
Volume air yg hrus ditambahkan sebesar 160 ml
Penjelasan:
Rumus pengenceran
M1 x v1 = M2 x v2
0,1 M x 40 ml = 0,025 M x v2
4 ml = 0,025 x v2
V2 = 4/ 0,025 ml
= 160 ml
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Jawaban:
Volume air yg hrus ditambahkan sebesar 160 ml
Penjelasan:
Rumus pengenceran
M1 x v1 = M2 x v2
0,1 M x 40 ml = 0,025 M x v2
4 ml = 0,025 x v2
V2 = 4/ 0,025 ml
= 160 ml