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Verified answer
Diketahui :Molaritas atau konsentrasinya 0,9M
ka = 10⁵
CH₃COOH merupakan asam lemah
ditanya : PH?
jawab:
rumus mencari [H⁺] asam lemah
[H⁺] =
maka pH = 3 - log 3
pH = 2,52