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ar O = 16
ar H = 1
mr Mg(OH)2 = ...?
= ( 1 × ar Mg) +( 2 × ar O) + (2 × ar H)
= (1 × 24) + (2 × 16) + (2 × 1)
= 24 + 32 + 2
= 58 gr/mol
Ar Mg = 24
Ar O = 16
Ar H = 1
Mr Mg(OH)₂ = Ar Mg + (2 x Ar O) + (2 x Ar H)
Mr Mg(OH)₂ = 24 + (2 x 16) + (2 x 1)
Mr Mg(OH)₂ = 58