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(3x-1)(3x-1)=0
x=1/3 dan x=1/3 (akar kembar)
b²-4ac= (-6)²-4(9)(1)= 36-36=0
2x²+2x+1=0
mungkin soal nya x²+2x+1=0
(x+1)(x+1)=0
x= -1 atau x= -1 (akar kembar)