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^2log (x+2)(x-5) < ^2log 8
(x+2) (x-5) < 8
x^2 - 3x - 10 < 8
x^2 - 3x - 18 < 0
(x - 6) (x + 3) < 0
x < 6 atau x > -3
Hp = { x | -3 < x < 6, x ∈ R}