Himpunan penyelesaian persamaan ² log x + ² log (x+6) = 4 adalah..
AtikaLestari
NILAI X = 2 ATAU X= -8
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slveka
caranya gimana?
IcukSugiarto
![\bold{\underline{Solution:}}\\\\~^{2}\log\ x+~^{2}\log\ (x+6)=4\\~^{2}\log\ (x(x+6))=~^{2}\log\ 2^{4}\\~^{2}\log\ x^{2}+6x=~^{2}\log\ 16\\ x^{2}+6x=16\\ x^{2}+6x-16=0\\(x+8)(x-2)=0\\x=-8~~~~~~~atau~~~~~~~x=2\\\\sehingga:\\\therefore~HP:\{x=2\}~~~~~~~~[karena\ x=-8\ tidak\ berlaku\ utk\ persamaan]](https://tex.z-dn.net/?f=%5Cbold%7B%5Cunderline%7BSolution%3A%7D%7D%5C%5C%5C%5C%7E%5E%7B2%7D%5Clog%5C+x%2B%7E%5E%7B2%7D%5Clog%5C+%28x%2B6%29%3D4%5C%5C%7E%5E%7B2%7D%5Clog%5C+%28x%28x%2B6%29%29%3D%7E%5E%7B2%7D%5Clog%5C+2%5E%7B4%7D%5C%5C%7E%5E%7B2%7D%5Clog%5C+x%5E%7B2%7D%2B6x%3D%7E%5E%7B2%7D%5Clog%5C+16%5C%5C+x%5E%7B2%7D%2B6x%3D16%5C%5C+x%5E%7B2%7D%2B6x-16%3D0%5C%5C%28x%2B8%29%28x-2%29%3D0%5C%5Cx%3D-8%7E%7E%7E%7E%7E%7E%7Eatau%7E%7E%7E%7E%7E%7E%7Ex%3D2%5C%5C%5C%5Csehingga%3A%5C%5C%5Ctherefore%7EHP%3A%5C%7Bx%3D2%5C%7D%7E%7E%7E%7E%7E%7E%7E%7E%5Bkarena%5C+x%3D-8%5C+tidak%5C+berlaku%5C+utk%5C+persamaan%5D "\bold{\underline{Solution:}}\\\\~^{2}\log\ x+~^{2}\log\ (x+6)=4\\~^{2}\log\ (x(x+6))=~^{2}\log\ 2^{4}\\~^{2}\log\ x^{2}+6x=~^{2}\log\ 16\\ x^{2}+6x=16\\ x^{2}+6x-16=0\\(x+8)(x-2)=0\\x=-8~~~~~~~atau~~~~~~~x=2\\\\sehingga:\\\therefore~HP:\{x=2\}~~~~~~~~[karena\ x=-8\ tidak\ berlaku\ utk\ persamaan]")
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