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x-2y+3z=4 | kali 1 x-2y+3z=4
2x+y-z =9 | kali 3 6x+3y-3z =27 | dikurangi
5x-y= -23 ...(2)
subtitusi 1 dan 2
x-y=-21
5x+y=-23
jadi 4x=44
x= 11
untuk y
masukin aja ke bilangan x-y+27=5
11-y = -21
y = 32
untuk z
2x + y - z = 9
22 + 33 -z =9
z = 44
ada ga jawabannya ???