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log x² < log (4(x+3))
*coret log-nya
x² < 4(x+3)
x² < 4x +12
x² - 4x - 12 < 0
(x-6)(x+2) < 0
*untuk X1 didapat
x-6 < 0
x < 6
*untuk X2 didapat
x+2 < 0
x < -2
himpunan penyelesaianya adalah x < 6 dan x < -2