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-2x + y = 0 --> y = 2x ... (ii)
2y + 3z = -1 ... (iii)
substitusi (ii) ke (iii)
2y + 3z = -1
2(2x) + 3z = -1
4x + 3z = -1 ..(iv)
karena persamaan (i) dan (iv) sama maka sistem persamaan tersebut tidak mempunyai penyelesaian.