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2x2+1x-6x-3
x(2x+1)-3(2x+1)
(x-3)(2x+1)
x=3 x=-2/3
2x² + x - 6x - 3 = 0
x(2x + 1) - 3(2x + 1) = 0
(x - 3) (2x + 1) = 0
x - 3 = 0
x₁ = 3
2x + 1 = 0
2x = -1
x₂ = -1/2
Himpunan Penyelesaian = {x₁, x₂} = {3, -1/2}