Question

Helppp please. tolong yaa

Answer 1

1).
= (3a-3b-3c)²
= (3a-3b-3c)(3a-3b-3c)
= 3a(3a-3b-3c) -3b(3a-3b-3c) -3c(3a-3b-3c)
= (9a² -9ab -9ac) + (-9ab +9b² + 9bc) + (-9ac +9bc +9c²)
= (9a²+9b²+9c²) + (-9+-9)ab + (-9+-9)ac + (9+9)bc
= 9a²+9b²+9c² -18ab -18ac + 18bc
= 9(a²+b²+c² -2ab -2ac +2bc)

2).
= (2x²+3xy+y²)/(x+y)
= (2x+y)(x+y)/(x+y)
= 2x+y