Question

Help number 1!!!!!!!!!!!!!!!

Answer 1

N = 2500 celah/cm
n = 2
θ = 30°
λ = ..............?

Penyelesiaan :

* Mencari d
d = 1/N
d = 1/2500
d = 4 x 10⁻⁴ cm
d = 4 x 10⁻⁶ m

* Mencari panjang gelombang
d sin θ  = n λ
4 x 10⁻⁶ . sin 30⁰ = 2 . λ
4 x 10⁻⁶ . ¹/₂ = 2 . λ
2 x 10⁻⁶ = 2 . λ
λ = 10⁻⁶ m

Jawaban A