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*Pertama cari tinggi segitiga tegak menggunakan pitagoras
1/2 x 10 = 5 cm
tinggi tegak = √5^2 + 12^2
= √25 + 144
= √169
= 13 cm
Luas segitiga tegak = 1/2 x 10 x 13
= 65 cm2
Luas 4 segitiga = 4 x 65 = 260 cm2
Luas alas = 10 x 10 = 100 cm2
Luas pembungkus = luas alas + luas segitiga
= 100 + 260
= 360 cm2