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a) Cl- anoda, dan katoda Na+
jadi Na+ + Cl- = NaCl
NaCl⇒ Na⁺+Cl⁻
rx anoda: 2Cl⁻⇒Cl₂ +2e
rx katoda: Na⁺+e⇒Na
hasilnya:NaCl+Na⁺+Cl⁻⇒ Cl₂+2Na
2. larutan NaCl
NaCl⇒ Na⁺+Cl⁻
rx anoda: 2Cl⁻⇒Cl₂ +2e
rx katode : 2H₂O+2e⇒2OH⁻+H₂
hasilnya:NaCl+Cl⁻+2H₂O⇒ Na⁺+Cl₂+2OH⁻+H₂
maaf kalau salah