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CH₃COOH 0,1 M dicampur dengan 100 mL NH₄OH 0,1 M
Pembahasan
mol = M.V
100 mL CH₃COOH 0,1 M
mol = 100 . 0,1 = 10 mmol = 0,01 mol
100 mL NH₄OH 0,1 M
mol = 100 . 0,1 = 10 mmol = 0,01
Reaksi habis karena mol CH3COOH dan Na4OH sama Terhidrolisis total
maka sifat larutaanya hanya tergantung dari Ka dan Kb
pH = - log H
= - log
= 7 - log 2
Semoga membantu :) D