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y=4-2x
gradien=-2 (koefisien x dengan syarat y beda ruas dan y=1)
sejajar= gradien sama
y-y1=m(x-x1)
y-5=-2(x-4)
y-5=-2x+8
y=13-2x
tegak lurus:m1.m2=-1
-0.5xm2=-1
m2=2
y-y1 = m(x-x1)
y-3=2(x-2)
y-3=2x-4
y=2x-1
2x+y= 2(4)+(5)
2x+y = 8+5
2x+y =13
2x+y-13=0
2. (2,3) tegak lurus dan mempunyai m =-1/2
(y-y1)=m(x-x1)
(y-3) = -1/2 (x-2)
2(y-3) = -1(x-2)
2y-6= -x+2
x+2y =2+6
x+2y-8 =0
semoga membantu