Respuesta:
Asumiendo que te refieres al área transversal
[tex]a = \pi \times {r }^{2} [/tex]
[tex]a = \pi \times {( {10}^{ - 3} )}^{2} [/tex]
[tex]a = {10}^{ - 6} \pi[/tex]
[tex]a = 3.14 \times {10}^{ - 6} \: \: {m}^{2} [/tex]
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Respuesta:
Asumiendo que te refieres al área transversal
[tex]a = \pi \times {r }^{2} [/tex]
[tex]a = \pi \times {( {10}^{ - 3} )}^{2} [/tex]
[tex]a = {10}^{ - 6} \pi[/tex]
[tex]a = 3.14 \times {10}^{ - 6} \: \: {m}^{2} [/tex]