a. To find the amount of packets with the mass of 0.2 kg, we need to find the modulo of [tex]\frac{9}{11}[/tex] divided by [tex]\frac{1}{5}[/tex]
[tex]\frac{9}{11} * 5[/tex]
= [tex]\frac{45}{11}[/tex]
= 4 mod 1
So the amount of packets with the mass of 0.2 kg is 4.
b. To find the mass of flour in the last packet, we can use the modulo from part a. Because the remainder of the division 45/11 is 1, then we can conclude that there are 4 packets of 0.2 kg with the last packet being 1/11 kg.
Hope this helps. Feel free to ask questions.
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glownshine
can you give me the working way to find b) question?
Jawab:
Penjelasan dengan langkah-langkah:
a. To find the amount of packets with the mass of 0.2 kg, we need to find the modulo of [tex]\frac{9}{11}[/tex] divided by [tex]\frac{1}{5}[/tex]
[tex]\frac{9}{11} * 5[/tex]
= [tex]\frac{45}{11}[/tex]
= 4 mod 1
So the amount of packets with the mass of 0.2 kg is 4.
b. To find the mass of flour in the last packet, we can use the modulo from part a. Because the remainder of the division 45/11 is 1, then we can conclude that there are 4 packets of 0.2 kg with the last packet being 1/11 kg.
Hope this helps. Feel free to ask questions.