Question

Hej . Kto mi to rozwiaże zad 1. a, b

Zad 2 . a,b

Answer 1

1.

a)

[tex]W(x) + P(x) = -3x^{5}+4x^{3}+2x-6+x^{6}+4x^{5}-4x^{3}+8x+6 =\\\\=x^{6}-3x^{5}+4x^{5}+4x^{3}-4x^{3}+2x+8x-6+6 = \boxed{x^{6}+x^{5}+10x}[/tex]

b)

[tex]W(x)+P(x) =0,2x^{3}-3x^{2}+0,25x+0,75+0,25+1,25x+3x^{2}-x^{3}=\\\\=0,2x^{3}-x^{3}-3x^{2}+3x^{2}+0,25x+1,25x+0,75+0,25 =\boxed{ -0,8x^{3}=1,5x+1}[/tex]

2.

a)

[tex]W(x) - P(x) = -2x^{5}+4x^{3}-9x+1 - (6 + 2x - 3x^{2}+8x^{3}-x^{4})=\\\\=-2x^{5}+4x^{3}-9x+1 - 6-2x+3x^{2}-8x^{3}+x^{4}=\\\\=-2x^{5}+x^{4}+4x^{3}-8x^{3}-9x-2x+1-6 = \boxed{-2x^{5}+x^{4}-4x^{3}-11x-5}[/tex]

b)

[tex]W(x) - P(x) = 0,75x^{6}-0,34x^{4}+0,27x^{3}-0,12-(0,88-0,34x^{4}-0,25x^{6})=\\\\=0,75x^{6}-0,34x^{4}+0,27x^{3}-0,12-0,88+0,34x^{4}+0,25x^{6} =\\\\=0,75x^{6}+0,25x^{6}-0,34x^{4}-0,34x^{4}+0,27x^{3}-0,12-0,88=\boxed{x^{6}+0,27x^{3}-1}[/tex]