Haya la hipotenusa de un triangulo cuyos catetos miden 15 cm y 23cm AYUDA POR FAVOR D:
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[tex]\bold{ {a}^{2} + {b}^{2} = {h}^{2} } \\ \\ \bold{h = \sqrt{ {(15})^{2} + ({23})^{2} } } \\ \\ \bold{h = \sqrt{225 + 529} } \\ \\ \bold{ h = \sqrt{754} = 27.459060 }[/tex]
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la hipotenusa sería: 27.45
espero te sirva (: