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entoncs x= cerdos y= gallina
x+y = 40
4x + 2y = 100
despejas x de la primera ec y la sustituyes en la 2da
x= 40-y
4(40-y) +2y = 100
160-4y +2y= 100
-4y+2y = 100-160
-2y= -60
y=-60/-2 = 30
x= 40-y = 40-30 = 10
por lo tanto x= 10 y= 30 osea 10 cerdos y 30 gallinas
2x + 4y =68
x= 20- y
2(20 -y) + 4y = 68
40 -2y +4y = 68
y = 14 cerdos
x = 6 gallinas