Hasilnya berapa ......... Question from @rannpoo

xcvi

Rasionalisasi...

$\displaystyle\sf \frac{\sqrt{5^{2019}}}{\sqrt{5^{2019}}-\sqrt{5^{2015}}}=\\\\\\\frac{\sqrt{5^{2019}}}{\sqrt{5^{2019}}-\sqrt{5^{2015}}}\times \frac{\sqrt{5^{2019}}+\sqrt{5^{2015}}}{\sqrt{5^{2019}}+\sqrt{5^{2015}}}=\\\\\\\frac{(\sqrt{5^{2019}})^2+\sqrt{5^{2019}}(\sqrt{5^{2015}})}{(\sqrt{5^{2019}})^2-(\sqrt{5^{2015}})^2}=\\\\\\\frac{5^{2019}+\sqrt{5^{2019}\cdot5^{2015}}}{5^{2019}-5^{2015}}=\\\\\\\frac{5^{2019}+\sqrt{5^{2019+2015}}}{5^{2019}-5^{2015}}=$

$\displaystyle\sf\frac{5^{2019}+\sqrt{5^{4034}}}{5^{2019}-5^{2015}}=\\\\\\\frac{5^{2019}+5^{4034\div2}}{5^{2019}-5^{2015}}=\\\\\\ \frac{5^{2019}+5^{2017}}{5^{2019}-5^{2015}}=\\\\\\\frac{\not5^{\not2015}(5^{4}+5^{2})}{\not5^{\not2015}(5^{4}-1)}=$

$\displaystyle\frac{625+25}{625-1}=\\\\\\\frac{650_{\div26}}{624_{\div26}}=\\\\\\\bf\frac{25}{24}$