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Verified answer
Jawaby ≤ x - 3
y ≤ x² - 4 .....}(-)
0 ≤ x - 3 - x² + 4
0 ≤ -x² + x + 1
atau
- x² + x + 1 ≥ 0
x² - x - 1 ≤ 0
x² - x ≤ 1
(x - 1/2)² ≤ 1 + 1/4
(x - 1/2) ≤ 1/2 √5
x ≤ 1/2 +1/2 √ 5 atau x ≥ 1/2 - 1/2 √5
x ≤ 1/2(1 +√5) atau x ≥ 1/2 (1- √5)