((x+3)(×-2))/(×-2)
(×+3)
2+3
5
Cara lain : aturan L'hopital (F'(x)/G'(x)) <= turunan atas dan bawah
(x²+x-6)/(x-2) => (2x+1-0)/(1-0) <= ini turunannya jadi gak pake simbol "=" karena 2x+1 ≠ (x²+x-6)/(x-2)
= 2x+1 <= masukkan x = 2
= 2.2 + 1
= 4+1
= 5
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((x+3)(×-2))/(×-2)
(×+3)
2+3
5
Cara lain : aturan L'hopital (F'(x)/G'(x)) <= turunan atas dan bawah
(x²+x-6)/(x-2) => (2x+1-0)/(1-0) <= ini turunannya jadi gak pake simbol "=" karena 2x+1 ≠ (x²+x-6)/(x-2)
= 2x+1 <= masukkan x = 2
= 2.2 + 1
= 4+1
= 5