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integral (2x√x - √x) dx, batas bawah 4, batas atas 9 =
integral (2x^(3/2) - x^(1/2))dx, bats bawah 4, batas atas 9 =
[2/(3/2+1)x^(3/2+1) - 1/(1/2)x^(1/2+1)], bats bawah 4, bats atas 9 =
[2/(5/2)x^(5/2) - 2x^(3/2)] batas bawah 4_ bats atas 9 =
[(4/5.x².√x) - (2.x.√x)], batas bawah 4, batas atas 9 =
((4/5.9².√9) - (2.9√9) - (4/5.4².√4) - (2.4.√4) =
(12/5 .81) - 54 - 128/5 - 16 =
972/5 - 54 - 128/5 - 16 =
(972-270-128-80)/5 = 494/5 = 98 4/5