Question

Hasil dari 2log9 x 3log5 x 5log32

A. 10
B. 12
C. 15
D. 16
E. 5

Answer 1

²log 9 × ³log 5 × ⁵log 32
= ²log 3² × ³log 5 × ⁵log 2⁵
= 2 ²log 3 × ³log 5 × 5 ⁵log 2
= 2 × 5 × ²log 3 × ³log 5 × ⁵log 2
= 10 × ²log 5 × ⁵log 2
= 10 × ²log 2
= 10 × 1
= 10

Answer 2

2log9 × 3log5 × 5log32
= 2log3^2 × 3log5 × 5log2^5
= 2 × 2log3 × 3log5 × 5 × 5log2
= 10 × (2log3 × 3log5 × 5log2)*
= 10 × 2log2 = 10 × 1 = 10 (A)

*alogb × blogc × cloga = aloga = 1