Jawab:[tex]\displaystyle=\bf\frac{5}{6}[/tex]
Penjelasan:[tex]\displaystyle\because n^{-a}=\frac{1}{n^a}\therefore\\\\2^{-1}+3^{-1}=\frac{1}{2^1}+\frac{1}{3^1}=\frac{1}{2}+\frac{1}{3}\\\\=\frac{3}{2(3)}+\frac{2}{3(2)}=\frac{3}{6}+\frac{2}{6}=\bf\frac{5}{6}[/tex]
(xcvi)
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Jawab:
[tex]\displaystyle=\bf\frac{5}{6}[/tex]
Penjelasan:
[tex]\displaystyle\because n^{-a}=\frac{1}{n^a}\therefore\\\\2^{-1}+3^{-1}=\frac{1}{2^1}+\frac{1}{3^1}=\frac{1}{2}+\frac{1}{3}\\\\=\frac{3}{2(3)}+\frac{2}{3(2)}=\frac{3}{6}+\frac{2}{6}=\bf\frac{5}{6}[/tex]
(xcvi)