→ minimum dan maksimum ←
y = 4x³ - 18x² + 15x - 20
syarat maks atau min → y' = 0
y' = 0
12x² - 36x + 15 = 0
4x² - 12x + 5 = 0
(2x - 1)(2x - 5) = 0
x = 1/2 atau x = 5/2
Utk x = 1/2
y = 4(1/2)³ - 18(1/2)² + 15(1/2) - 20
y = 1/2 - 9/2 + 15/2 - 20
y = -16,5 → maksimum
Utk x = 5/2
y = 125/2 - 225/2 + 75/2 - 20
y = -32,5 → minimum
Hasil bagi pembuat min thd maks
5/2 : 1/2 = 5 → jawaban
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→ minimum dan maksimum ←
y = 4x³ - 18x² + 15x - 20
syarat maks atau min → y' = 0
y' = 0
12x² - 36x + 15 = 0
4x² - 12x + 5 = 0
(2x - 1)(2x - 5) = 0
x = 1/2 atau x = 5/2
Utk x = 1/2
y = 4(1/2)³ - 18(1/2)² + 15(1/2) - 20
y = 1/2 - 9/2 + 15/2 - 20
y = -16,5 → maksimum
Utk x = 5/2
y = 125/2 - 225/2 + 75/2 - 20
y = -32,5 → minimum
Hasil bagi pembuat min thd maks
5/2 : 1/2 = 5 → jawaban