Harga x yang memenuhi
![( \frac{1}{3} )^{3} \sqrt[3]{ 3^{5x+2} }](https://tex.z-dn.net/?f=%28+%5Cfrac%7B1%7D%7B3%7D+%29%5E%7B3%7D+%5Csqrt%5B3%5D%7B+3%5E%7B5x%2B2%7D+%7D+ "( \frac{1}{3} )^{3} \sqrt[3]{ 3^{5x+2} }")
= 3
adalah....
adalah....
fendyjuniar
![( \frac{1}{3} )^3 \sqrt[3]{3^{5x+2}} = 3^1 \\ (3^{{-1}^3})(3^ {\frac{5x+2}{3}} ) = 3^1 \\ (3^{-3})(3^ {\frac{5x+2}{3}} ) = 3^1 \\ 3^{{\frac{5x+2}{3}}-3} = 3^1 \\ \frac{5x+2-9}{3} = 1 \\ 5x+2-9 = 3 \\ 5x = 10 \\ x = 2](https://tex.z-dn.net/?f=%28+%5Cfrac%7B1%7D%7B3%7D+%29%5E3++%5Csqrt%5B3%5D%7B3%5E%7B5x%2B2%7D%7D+%3D+3%5E1+%5C%5C++%283%5E%7B%7B-1%7D%5E3%7D%29%283%5E+%7B%5Cfrac%7B5x%2B2%7D%7B3%7D%7D+%29+%3D+3%5E1+%5C%5C++%283%5E%7B-3%7D%29%283%5E+%7B%5Cfrac%7B5x%2B2%7D%7B3%7D%7D+%29+%3D+3%5E1+%5C%5C+3%5E%7B%7B%5Cfrac%7B5x%2B2%7D%7B3%7D%7D-3%7D+%3D+3%5E1+%5C%5C+++%5Cfrac%7B5x%2B2-9%7D%7B3%7D+%3D+1+%5C%5C+5x%2B2-9+%3D+3+%5C%5C+5x+%3D+10+%5C%5C+x+%3D+2 "( \frac{1}{3} )^3 \sqrt[3]{3^{5x+2}} = 3^1 \\ (3^{{-1}^3})(3^ {\frac{5x+2}{3}} ) = 3^1 \\ (3^{-3})(3^ {\frac{5x+2}{3}} ) = 3^1 \\ 3^{{\frac{5x+2}{3}}-3} = 3^1 \\ \frac{5x+2-9}{3} = 1 \\ 5x+2-9 = 3 \\ 5x = 10 \\ x = 2")
0 votes
Thanks 1
izharulhaq78
![\displaystyle \text{ingat sifat - sifat berikut :}\\\sqrt[b]{a^c}=a^{\frac{c}{b}}\\a^{f(x)}=a^b\to f(x)=b](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Ctext%7Bingat+sifat+-+sifat+berikut+%3A%7D%5C%5C%5Csqrt%5Bb%5D%7Ba%5Ec%7D%3Da%5E%7B%5Cfrac%7Bc%7D%7Bb%7D%7D%5C%5Ca%5E%7Bf%28x%29%7D%3Da%5Eb%5Cto+f%28x%29%3Db "\displaystyle \text{ingat sifat - sifat berikut :}\\\sqrt[b]{a^c}=a^{\frac{c}{b}}\\a^{f(x)}=a^b\to f(x)=b")
![\displaystyle \left(\frac13\right)^3\sqrt[3]{3^{5x+2}}=3\\\frac1{27}\sqrt[3]{3^{5x+2}}=3\\\sqrt[3]{3^{5x+2}}=3\times27\\3^{\frac{5x+2}3}=81\\3^{\frac{5x+2}3}=3^4\\\\\therefore\\\frac{5x+2}3=4\\5x+2=4\times3\\5x=12-2\\5x=10\\\boxed{\boxed{x=2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cleft%28%5Cfrac13%5Cright%29%5E3%5Csqrt%5B3%5D%7B3%5E%7B5x%2B2%7D%7D%3D3%5C%5C%5Cfrac1%7B27%7D%5Csqrt%5B3%5D%7B3%5E%7B5x%2B2%7D%7D%3D3%5C%5C%5Csqrt%5B3%5D%7B3%5E%7B5x%2B2%7D%7D%3D3%5Ctimes27%5C%5C3%5E%7B%5Cfrac%7B5x%2B2%7D3%7D%3D81%5C%5C3%5E%7B%5Cfrac%7B5x%2B2%7D3%7D%3D3%5E4%5C%5C%5C%5C%5Ctherefore%5C%5C%5Cfrac%7B5x%2B2%7D3%3D4%5C%5C5x%2B2%3D4%5Ctimes3%5C%5C5x%3D12-2%5C%5C5x%3D10%5C%5C%5Cboxed%7B%5Cboxed%7Bx%3D2%7D%7D "\displaystyle \left(\frac13\right)^3\sqrt[3]{3^{5x+2}}=3\\\frac1{27}\sqrt[3]{3^{5x+2}}=3\\\sqrt[3]{3^{5x+2}}=3\times27\\3^{\frac{5x+2}3}=81\\3^{\frac{5x+2}3}=3^4\\\\\therefore\\\frac{5x+2}3=4\\5x+2=4\times3\\5x=12-2\\5x=10\\\boxed{\boxed{x=2}}")
2 votes
Thanks 1
More Questions From This User See All
