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2x + 1y = 140.000 | x 2 | 4x + 2y = 280.000
3x + 2y = 235.000 | x 1 | 3x + 2y = 235.000 hasilnya di kurang
jadi 1x + 0 = 45.000
jadi harga satu baju = 45.000
jadi harga 1 celana = 2x + 1y = 140.000
2 (45.000) + 1y = 140.000
90.000 + 1y = 140.000
1y = 140 .000 - 90.000 (pindah ruas)
y = 50.000
jadi harga 4 baju dan 5 celana adalah :
(4 x 45.000) + ( 5 x 50.000) = 180.000 + 250.000
= 430.000
baju = X
celana = y
eliminas x
2X + y = 140000 (x3) = 6x + 3y = 420000
3X + 2y = 235000 (x2) = 6x + 4y = 470000 _
-y = -50000
y = 50000
subtitusi y ke 2X + y = 140000
2X + y = 140000
2X + 50000 = 140000
2X = 140000 - 50000
2X = 90000
X = 90000/2
X = 45000
harga 4 baju dan 5 celana
4X + 5y
4(45000) + 5(50000)
180000 + 250000
430000