Question

HARAP BANTUANNYA SOAL INTEGRAL

Answer 1

8. ∫(π/₂...0)   2x + sin x dx =
= | x² - cos x| (π/₂ ...0)
= (π/₂)² -(0)²  - (cos π/₂ - cos 0)
= ¹/₄ π² - (0-1)
= ¹/₄ π² + 1

9. ∫ x sin (x² +1) dx
=  (x / 2x) (- cos (x² + 1) + c
=  - ¹/₂ cos (x² + 1) + c

10. ∫ (6x² - 4x ) √(x³ - x² - 1) dx
= (6x² -4x)/(3x² - 2x) (2/3) (√(x³ -x² -1)³/² + c
= 2(3x²-2x)/(3x²-2x) (2/3) (√(x³ -x² -1)³/² + c
= 4/3 √(x³ - x² -1)³/² + c
= 4/3 (x³ -x² -1) √(x³ -x² -1) + C