Hambatan 20 Ω dialiri arus 3 A. Jika lama arus mengalir setengah menit , berapakah energi yang hilan.... Question from @Bryanadamp09pceywj

Verified answer

Yang diketahui :
Hambatan (R) = 20 ohm
Kuat arus (I) = 3 A
Waktu (t) = 0, 5 menit = 30 s

Yang ditanya Energi (W)

Pembahasan.
Persamaan Energi Listrik.
W = V I t

Dimana, V = I R sehingga

W = I R I t

W = I^2 R t

W = (3 A)^2 20 ohm 30 s
W = 5400 J

Kesimpulan.
Jadi energinya sebesar 5400 J.

=====\\(^_^) //=====

Mapel : Fisika
Materi : Rangkain Arus searah
- Energi Listrik

JamesPrescottJoule LISTRIK DINAMIS

diketahui:
R = 20 Ω
I = 3 Ampere
t = 1/2 menit = 1/2 . 60 = 30 sekon

ditanya:
W?

jawab:
P = W / t
W = P . t
W = V . I . t
W = I . R . I . t
W = I² . R . t
W = 3² . 20 . 30
W = 9 . 600
W = 5400 Joule

jadi energi yang hilang adalah 5400 Joule

Verified answer

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