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x y = 4x + 7 P(x, y)
0 7 P1(0, 7)
- 7/4 0 P2(-7/4, 0)
PUNTO MAS PRÓXIMO DE P(0, 0) ES P2(-7/4, 0)
Recomiendo
- trazar la recta en un plano cartesiano
- determinar las distancias P(0, 0) - P1(0,7) y P(0,0) - P2(-7/4, 0)