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2do X+1=?
3er X+2=?
X²+(X+2)²+ 79 = 3(X+1)²
X² + X² + 4X+ 4 +79 = 3(X²+2X+1)
2X² +4X + 83 = 3X² +6X +3
3X² -2X2² +6X - 4X +3 - 83= 0
X² +2X - 80= 0
(X + 10)(x - 8)=0
(X + 10) =0 ó (x - 8)=0
X = - 10 ó X = 8
Solo tomamos el x=8
1er X =8
2do X+1 = 8+1 =9
3er X+2 = 8+2=10
Los números consecutivos son 8,9,10