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x ; x+1 , x+2
x² + (x+1)² = (x+2)² + 12
x² + x² + 2x +1 = x² + 4x + 4 +12
2x² + 2x +1 = x² + 4x + 16
x² - 2x - 15 =0
x -5 -5x
x 3 3x
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-15 -2x
x-5 =0 ∧ x+3 =0
x = 5 ∧ x = -3 dos soluciones
los números son 5 ; 6 ; 7 y -3 ; -2 ; -1