Question

Hallar la media diferencial de:
I. 40 y 32 III 56 86
II. 28 y 52 IV 27 y 19





AYUDA PORFA!! SOLO ME FALTA LA 3 Y LA 4 PORFA AYUDA ​

Answer 1

Respuesta:

 [tex]\Huge\underline{\underline{\texttt{\Large\boldsymbol{Media \ Diferencial}}}}}}[/tex]

1. [tex]\Large\boldsymbol{ a - b = b - d}[/tex]
2. [tex]\Large\boldsymbol{ b + b = a + d}[/tex]
3. [tex]\Large\boldsymbol{ 2b = a + d }[/tex]
4. [tex]\Large\boldsymbol{ b =\dfrac{ (a + d)}{2} }[/tex]

Hallar la media diferencial de:

I. 40 y 32

[tex]\Large\boldsymbol{ b =\dfrac{ (a + d)}{2} }[/tex]

[tex]\Large\boldsymbol{ }b =\dfrac{ (40+ 32)}{2} }[/tex]

[tex]\Large\boldsymbol{ }b =\dfrac{ 72}{2} }[/tex]

[tex]\Large\boldsymbol{ }b =36 }[/tex]

II. 28 y 52

[tex]\Large\boldsymbol{ }b =\dfrac{ (28+ 52)}{2} }[/tex]

[tex]\Large\boldsymbol{ }b =\dfrac{ 80 }{2} }[/tex]

[tex]\Large\boldsymbol{ }b =40}[/tex]

III 56 y 86

[tex]\Large\boldsymbol{ }b =\dfrac{ (56+ 86)}{2} }[/tex]

[tex]\Large\boldsymbol{ }b =\dfrac{ 142 }{2} }[/tex]

[tex]\Large\boldsymbol{ }b =71 }[/tex]

IV 27 y 19

[tex]\Large\boldsymbol{ }b =\dfrac{ (27+ 19)}{2} }[/tex]

[tex]\Large\boldsymbol{ }b =\dfrac{ 46 }{2} }[/tex]

[tex]\Large\boldsymbol{ }b =23 }[/tex]

Explicación paso a paso:https://brainly.lat/tarea/941019

Answer 2

Verified answer

Bien veamos

Hagamos cada uno

[tex]40 - x = x - 32 \\ 40 + 32 = x + x \\ 72 = 2x \\ \\ \frac{72}{2} = \frac{2x}{2} \\ \mathbf{ \green{36 = x}}[/tex]

siguiente

[tex]52 - x = x - 28 \\ 52 + 28 = x + x \\ 80 = 2x \\ \\ \frac{80}{2} = \frac{2x}{2} \\ \mathbf{ \green{40 = x}}[/tex]

[tex]86 - x = x - 56\\ 86 + 56= x + x \\ 142 = 2x \\ \\ \frac{142}{2} = \frac{2x}{x} \\ \mathbf{ \green{71 = x}}[/tex]

sigamos

[tex]27 - x = x - 19 \\ 27 + 19 = x + x \\ 46 = 2x \\ \\ \frac{46}{2} = \frac{2x}{2} \\ \mathbf{ \green{x = 23 }}[/tex]

espero haberte ayudado :3